例如输入15，由于1+2+3+4+5=4+5+6=7+8=15，所以输出3个连续序列1-5、4-6和7-8。

#include 
    
     #include 
     
      using std::cin;using std::cout;using std::endl;using std::vector;vector< vector
      
        > consecaddend(int n){    vector< vector
       
         > vec;    vector
        
          iv;    int i, j;    //i是序列的长度，最大不超过sqrt(2n)    //当n/i == i/2时应判断：如果i是奇数则停止循环，否则会得到以0开头的序列    //如：10/4 == 10/5 == 4/2 == 5/2 == 2 （感谢指正）    for (i = 2; ((j = n/i) > i/2) || (j == i/2) && (i%2 == 0); i++)        if (i%2) {            //i为奇数，仅当n能被i整除时存在这样的序列            if (n%i == 0) {                j -= i/2;                for (int k = 0; k != i; ++k)                    iv.push_back(j++);                vec.push_back(iv);                iv.clear();            }        } else {            //i为偶数，仅当n/i小数部分为0.5时存在这样的序列            if (n%i != 0 && 2*n%i == 0) {                j -= i/2 - 1;                for (int k = 0; k != i; ++k)                    iv.push_back(j++);                 vec.push_back(iv);                iv.clear();            }        }    return vec;}int main(void){    int x;    vector< vector
         
           > v; while (cin >> x) { v = consecaddend(x); for(vector< vector
          
            >::iterator viter = v.begin(); viter != v.end(); ++viter) { for(vector
           
            ::iterator iter = viter->begin(); iter != viter->end(); ++iter) cout << *iter << " "; cout << endl; } v.clear(); } return 0;}